In case you were curious, logs are basically just another way of writing exponents, but so that the exponent is the solution. Saying log<sub>a</sub>b=c means that a<sup>c</sup>=b. If a is not given, it is assumed to be 10.

In case you were curious, logs are basically just another way of writing exponents, but so that the exponent is the solution. Saying log<sub>a</sub>b=c means that a<sup>c</sup>=b. If a is not given, it is assumed to be 10.

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Assuming I was correct in the assumption that Lysy intended "(log<sub>10</sub>2)*6400," not "log<sub>2</sub>6400," "log2=x" is the same as saying 10<sup>x</sup>=2, and x=about 0.301.

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Assuming I was correct in the assumption that Lysy intended "(log<sub>10</sub>2)*6400," not "log<sub>2</sub>6400," "log2=x" is the same as saying 10<sup>x</sup>=2, and x=about 0.301, which is of course only one part of Lysy's damage.

Latest revision as of 04:51, April 18, 2017

In case you were curious, logs are basically just another way of writing exponents, but so that the exponent is the solution. Saying log_{a}b=c means that a^{c}=b. If a is not given, it is assumed to be 10.

Assuming I was correct in the assumption that Lysy intended "(log_{10}2)*6400," not "log_{2}6400," "log2=x" is the same as saying 10^{x}=2, and x=about 0.301, which is of course only one part of Lysy's damage.

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